It’s actually quite simple, here’s Berezza’s method for abbreviating
numerals ( Provides a lot more options than compact notation parameter );
> local Suffixes =
> {"k","M","B","T","qd","Qn","sx","Sp","O","N","de","Ud","DD","tdD","qdD","QnD","sxD","SpD","OcD","NvD","Vgn","UVg","DVg","TVg","qtV","QnV","SeV","SPG","OVG","NVG","TGN","UTG","DTG","tsTG","qtTG","QnTG","ssTG","SpTG","OcTG","NoTG","QdDR","uQDR","dQDR","tQDR","qdQDR","QnQDR","sxQDR","SpQDR","OQDDr","NQDDr","qQGNT","uQGNT","dQGNT","tQGNT","qdQGNT","QnQGNT","sxQGNT","SpQGNT",
> "OQQGNT","NQQGNT","SXGNTL"}
>
>
> function Convert(Input) local Negative = Input < 0 Input =
> math.abs(Input)
>
> local Paired = false for i,v in pairs(Suffixes) do if not (Input
> >= 10^(3*i)) then Input = Input / 10^(3*(i-1)) local isComplex = (string.find(tostring(Input),".") and string.sub(tostring(Input),4,4)
> ~= ".") Input = string.sub(tostring(Input),1,(isComplex and 4) or
> 3) .. (Suffixes[i-1] or "") Paired = true break; end end if
> not Paired then local Rounded = math.floor(Input) Input =
> tostring(Rounded) end if Negative then return "-"..Input end
> return Input -- returns 1.0k for example end Now to add commas to a
numeral , or to abbreviate it that style is a different function;
> function AbbreviateNumeral(numeral) if numeral then local
> left,num,right = string.match(numeral,'^([^%d]*%d)(%d*)(.-)$')
> return left..(num:reverse():gsub('(%d%d%d)','%1,'):reverse())..right
-- returns for example 1,000, it gets every 3 zeros and adds a comma end end All you have to do is call one of these functions and it’ll
return a number abbreviated!
Use Kensizo suggested.
https://devforum.roblox.com/t/how-can-i-turn-a-number-to-a-shorter-number-i-dont-know-how-to-explain-click-to-understand-3/649496/3
In my game that is upcoming, Samurai Legends, it’s easier for players to understand Berezza’s conversion it seems to be, but whichever you prefer and think is cleaner is the one you should go with!
Unlike your method
it can also support negative numerals, which is pretty cool.
