Counting occurences of an item in an ndarray based on multiple conditions?

How do you specify multiple conditions in the np.count_nonzero function.

This is for counting the numbers inside an array that have a value between two values. I know you can subtract the outcomes of two individual count_nonzero lines. But I would like to know if there is an easy way to pass multiple conditions to np.count_nonzero.

import numpy as np

array = np.array([[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
                  [0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0],
                  [0, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 1, 1, 1, 0],
                  [0, 1, 1, 2, 3, 3, 3, 3, 3, 3, 3, 3, 2, 1, 1, 0],
                  [0, 1, 2, 3, 4, 4, 4, 4, 4, 4, 4, 4, 3, 2, 1, 0],
                  [0, 2, 3, 4, 5, 6, 6, 6, 6, 6, 6, 5, 4, 3, 2, 0],
                  [0, 2, 3, 4, 5, 6, 7, 8, 8, 7, 6, 5, 4, 3, 2, 0],
                  [0, 2, 3, 4, 5, 6, 6, 6, 6, 6, 6, 5, 4, 3, 2, 0],
                  [0, 1, 2, 3, 4, 4, 4, 4, 4, 4, 4, 4, 3, 2, 1, 0],
                  [0, 1, 1, 2, 3, 3, 3, 3, 3, 3, 3, 3, 2, 1, 1, 0],
                  [0, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 1, 1, 1, 0],
                  [0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0],
                  [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
                  [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]])

# Count occurences of values between 5 and 8  in array.
result1 = np.count_nonzero(array <= 8)
result2 = np.count_nonzero(array <= 5)
result = result 1 - result2

I would like to know if there is a way that looks something like:

np.count_nonzero(array >= 6 and array <= 8)