I have tried this case:
let a = { id: 1, name: "Misha" };
function b(id: number, name: string) {
}
b(...a);
I need that all properties of object will be applied as parameters
How to use spread as parameters in function?
Viewed 1543
2 Answers
TypeScript doesn't support spreading objects to parameter names.
If it's possible for you to change the function signature though, you can expect an object of a compatible type as the first function parameter, like this:
// interface name is just an example
interface IUser {
id: number;
name: string;
}
let a: IUser = { id: 1, name: "Misha" };
function b({ id, name }: IUser) {
console.log(`User ID is ${id} and name is "${name}"`);
}
b(a);
TypeScript does support spreading objects to parameter names.
Write the three dots before the parameter name, and an array operator next to the type.
Example :
function add(x: number, ...vals: number[])
Related