Running Selenium without GUI : Status code 64

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I'm trying to run Selenium in Headless mode in a Linux machine without GUI. The problem is that I'm getting a WebDriverException and I can't find anywhere what the status code 64 means.

Does anyone know where to find the status code definitions ?

Code :

from pyvirtualdisplay import Display
from selenium import webdriver

display = Display(visible=0, size=(1024, 768))
display.start()

path = '/home/workspace/geckodriver'
driver = webdriver.Firefox(executable_path=path, service_args=['--verbose', '--log-path=/tmp/firefox.log']) 

# website testing functionality: 
driver.get('https://python.org') 
print(driver.title)

Error :

WebDriverException: Message: Service /home/workspace/geckodriver unexpectedly exited. Status code was: 64

pyvirtualdisplay geckodriver selenium firefox python
1 Answers

I'm not sure what the status code means, but try to update the Firefox webdriver. Updating the Firefox webdriver fixed it for me.

user_112379380
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