Swift Pong(No SpriteKit): Detect side of paddle that the ball hit

user_8560567 0
Viewed 116

Currently, I am making a pong game in Swift(without SpriteKit) that is one player: the ball can bounce off all sides of the view. After some research, I used this algorithm to detect collisions:

if (rect1.x < rect2.x + rect2.width &&
    rect1.x + rect1.width > rect2.x &&
    rect1.y < rect2.y + rect2.height &&
    rect1.y + rect1.height > rect2.y) {
        // collision detected!
}

This works fine, but how can I detect which side of the paddle that the ball hit?

I need to know this because: if the ball hits the bottom or top side of the paddle, I would multiply the y increment by -1. If the ball hits the left or right side of the paddle, I would multiply the x increment by -1.

pong collision-detection swift
2 Answers

If rect1 and rect2 are both CGRect then you can get the mid point with...

rect1.midY

And

rect2.midY

You can then find if the mid point ball (whichever one it is) is higher or lower than the midpoint of the paddle.

if rect1.midY >= rect2.midY

Etc...

On a side note, you’d be much better off using SpriteKit for this. But if you’re just doing it for fun then carry on. Hope it works out. :-)

user_4210180

I found a decent(but not very good) solution. This function returns true if the ball touches either the left or the right side of the paddle, and false if the ball touches either the top or bottom of the paddle.

func touchHorizontalPaddle() -> Bool {
    if abs(ball.origin.x + ball.width - paddle.origin.x) < 1 || 
       abs(ball.origin.x - (paddle.origin.x + paddle.width)) < 1 {
        return true
    }
    return false
}

The main issue with this function is that the "less than 1" part is hardcoded. Thus, if the ball speed is too fast, or the increment is too large, the conditional statement may get messed up. Overall, though, it works pretty well.

user_85605670
Related