How to sum a Set[ValidatedNel[String, Double]]?

Viewed 147

I have this:

Set[ValidatedNel[String, Double]] 

and I would like to sum the Doubles in it to get:

ValidatedNel[String, Double]

If some elements in the values are then I would like to have matching strings.

I played with Set.sum and Numeric to no avail...

Here is the test of what I would like to achieve:

  test("Summing ValidatedNel works") {
    val val1: ValidatedNel[String, Double] = Valid(1.0)
    val val2: ValidatedNel[String, Double] = Valid(2.0)
    val values: Set[ValidatedNel[String, Double]] = Set(val1, val2)

    val validatedNelNumeric: Numeric[ValidatedNel[String, Double]] = ???
    val sum = values.sum(validatedNelNumeric)

    assert(sum == Valid(3.0))
  }

I don't manage to create the validatedNelNumeric...

1 Answers

To start with: it feels a little weird to use a set in this case (for a collection of Validated[..., Double] values). What part of the Set semantics do you care about? The unorderedness? Uniqueness?

In general the most straightforward way to sum up elements that have a Monoid instance is to use the combineAll method for things with a Foldable instance—for example a List (but not Set).

import cats.data.{ Validated, ValidatedNel }
import cats.instances.double._, cats.instances.list._
import cats.syntax.foldable._
// or just import cats.implicits._

val val1: ValidatedNel[String, Double] = Validated.valid(1.0)
val val2: ValidatedNel[String, Double] = Validated.valid(2.0)
val bad1: ValidatedNel[String, Double] = Validated.invalidNel("foo")
val bad2: ValidatedNel[String, Double] = Validated.invalidNel("bar")

val values = Set(val1, val2)
val withSomeBadOnes = Set(val1, bad1, val2, bad2)

And then:

scala> values.toList.combineAll
res0: cats.data.ValidatedNel[String,Double] = Valid(3.0)

scala> withSomeBadOnes.toList.combineAll
res1: cats.data.ValidatedNel[String,Double] = Invalid(NonEmptyList(foo, bar))

I'm guessing that's what you mean by "If some elements in the values are then I would like to have matching strings"?

You could also use SortedSet, since Cats provides a Foldable instance for SortedSet, but it's not as convenient:

scala> import cats.implicits._
import cats.implicits._

scala> import scala.collection.immutable.SortedSet
import scala.collection.immutable.SortedSet

scala> (SortedSet.empty[ValidatedNel[String, Double]] ++ values).combineAll
res2: cats.data.ValidatedNel[String,Double] = Valid(3.0)

scala> (SortedSet.empty[ValidatedNel[String, Double]] ++ withSomeBadOnes).combineAll
res3: cats.data.ValidatedNel[String,Double] = Invalid(NonEmptyList(bar, foo))

You could also use the standard fold and the |+| operator for monoids:

scala> values.fold(Validated.valid(0.0))(_ |+| _)
res4: cats.data.ValidatedNel[String,Double] = Valid(3.0)

To sum up: you can't call combineAll directly on your Set, since Cats doesn't provide a Foldable for Set. I'd suggest carefully reconsidering your use of the Set in any case, but if you decide to stick with it, you have a few options: convert to List or SortedSet like I have above, use the standard fold on Set, or finally write your own Foldable[Set] or use the one from alleycats.

Related