How to split seaborn legend into multiple columns?

user_2230045 0
Viewed 8419

I use a relplot with different hue and style and would like to show the respective legend entries besides instead of below each other.

So currently I get a legend like this:

relplot legend with hue and style labels below each other

Instead I would like to have a single legend looking something like this:

relplot legend with hue and style labels besides each other

How can this be done?

I tried setting the following but that had no effect:

plot._legend
leg._ncol = 2
leg.handleheight = 1  # restricting the height

Minimal working example to solve this problem:

import pandas as pd
import seaborn as sns

columns = ['category1', 'category2', 'category3', 'time', 'value']

data = [['content1', 'other1', 'critera1', 0, 0.1], ['content1', 'other1', 'critera1', 1, 0.4], ['content1', 'other1', 'critera1', 2, 0.7], ['content2', 'other1', 'critera1', 0, 0.2], ['content2', 'other1', 'critera1', 1, 0.6], ['content2', 'other1', 'critera1', 2, 0.8], ['content1', 'other2', 'critera1', 0, 0.0], ['content1', 'other2', 'critera1', 1, 0.2], ['content1', 'other2', 'critera1', 2, 0.8], ['content2', 'other2', 'critera1', 0, 0.3], ['content2', 'other2', 'critera1', 1, 0.6], ['content2', 'other2', 'critera1', 2, 0.5], [
    'content1', 'other1', 'critera2', 0, 0.1], ['content1', 'other1', 'critera2', 1, 0.4], ['content1', 'other1', 'critera2', 2, 0.7], ['content2', 'other1', 'critera2', 0, 0.2], ['content2', 'other1', 'critera2', 1, 0.6], ['content2', 'other1', 'critera2', 2, 0.8], ['content1', 'other2', 'critera2', 0, 0.0], ['content1', 'other2', 'critera2', 1, 0.2], ['content1', 'other2', 'critera2', 2, 0.8], ['content2', 'other2', 'critera2', 0, 0.3], ['content2', 'other2', 'critera2', 1, 0.6], ['content2', 'other2', 'critera2', 2, 0.5], ]

df = pd.DataFrame(data, columns=columns)

plot = sns.relplot(x='time', y='value', col='category3', hue='category1', style='category2', kind="line", col_wrap=2, data=df)

leg = plot._legend
leg.set_bbox_to_anchor((0.5, 1.3, 0, 0))
leg._loc = 9

minimal working example output

seaborn legend matplotlib python
4 Answers

Since you seem to want to place the legend above the plots, I would instruct seaborn to not reserve space on the right for the legend using legend_out=False. Then it's just a matter of getting the handles and labels created by seaborn, and generate a new legend using ncol=2. Note that this will only work well if you have the same number of elements in both columns, otherwise things will get messy.

plot = sns.relplot(x='time', y='value', col='category3', hue='category1', style='category2', kind="line", col_wrap=2, data=df, facet_kws=dict(legend_out=False))
h,l = plot.axes[0].get_legend_handles_labels()
plot.axes[0].legend_.remove()
plot.fig.legend(h,l, ncol=2) # you can specify any location parameter you want here
user_13560000

Final solution thanks to @DizietAsahi

import pandas as pd
import seaborn as sns

columns = ['category1', 'category2', 'category3', 'time', 'value']

data = [['content1', 'other1', 'critera1', 0, 0.1], ['content1', 'other1', 'critera1', 1, 0.4], ['content1', 'other1', 'critera1', 2, 0.7], ['content2', 'other1', 'critera1', 0, 0.2], ['content2', 'other1', 'critera1', 1, 0.6], ['content2', 'other1', 'critera1', 2, 0.8], ['content1', 'other2', 'critera1', 0, 0.0], ['content1', 'other2', 'critera1', 1, 0.2], ['content1', 'other2', 'critera1', 2, 0.8], ['content2', 'other2', 'critera1', 0, 0.3], ['content2', 'other2', 'critera1', 1, 0.6], ['content2', 'other2', 'critera1', 2, 0.5], [
    'content1', 'other1', 'critera2', 0, 0.1], ['content1', 'other1', 'critera2', 1, 0.4], ['content1', 'other1', 'critera2', 2, 0.7], ['content2', 'other1', 'critera2', 0, 0.2], ['content2', 'other1', 'critera2', 1, 0.6], ['content2', 'other1', 'critera2', 2, 0.8], ['content1', 'other2', 'critera2', 0, 0.0], ['content1', 'other2', 'critera2', 1, 0.2], ['content1', 'other2', 'critera2', 2, 0.8], ['content2', 'other2', 'critera2', 0, 0.3], ['content2', 'other2', 'critera2', 1, 0.6], ['content2', 'other2', 'critera2', 2, 0.5], ]

df = pd.DataFrame(data, columns=columns)

plot = sns.relplot(x='time', y='value', col='category3', hue='category1', style='category2', kind="line",
                   col_wrap=2, data=df)

handles, labels = plot.axes[0].get_legend_handles_labels()
plot._legend.remove()
plot.fig.legend(handles, labels, ncol=2, loc='upper center', 
                bbox_to_anchor=(0.5, 1.15), frameon=False)

solution

user_41243170

Use ncol

ax = sns.barplot(x="X", y="Y", data=data)    
ax.legend(loc='upper left',ncol=2, title="Title")
user_10888210

The answer given by @DizietAsahi was not working for my case. However, I was able to do this with the sns.move_legend() utility function, which can be used to modify the legend of a plot.

sns.move_legend(ax, "upper center", bbox_to_anchor=(0.5, 1.15), 
                ncol=2)
user_111099100
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