How do I check if a variable derives from a class?

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I want to print variables of many types. I've made a class named IStringable, and some classes that derive from it. In my PrintVariable function I want to check whether the parameter derives from IStringable, and if it does then print it.

class IStringable {
public:
    virtual ~IStringable() { }
    virtual std::string ToString() const = 0;
}

class Person : public IStringable {
public:
    Person(const std::string name) : _name(name) { }
    virtual std::string ToString() const { return _name; }
private:
    std::string _name;
}

// This does not work as intended, as I don't know how it could be implemented
template <>
void PrintVariable<IStringable>(const IStringable& var) {
    std::cout << var.ToString() << std::endl;
}

int main() {
    Person p("Foo");
    PrintVariable(p);
}

So far I've worked around this problem by just using std::cout << p.ToString() << std::endl; instead, but I'm wondering if there's a better solution to this.

inheritance c++
1 Answers

You don't need a template:

void PrintVariable(const IStringable& var) {
    std::cout << var.ToString() << '\n';
}

Only calls to PrintVariable with object convertible to IStringable are legal:

Person p("Alice");
struct Bob {} b;
PrintVariable(p); // OK
PrintVariable(b); // ill-formed: no conversion from Bob to const IStringable&

Additionally, you could redesign PrintVariable as an operator:

std::ostream& operator<<(std::ostream& os, IStringable const& rhs)
{
    return os << rhs.ToString();
}

So you could write:

Person p("Alice");
std::cout << p << '\n';

As it appears from comments, OP whants a way to log things. A minimal implementation would be:

#include <string_view>
#include <type_traits>
#include <iostream>

namespace Logger
{
    struct IStringable
    {
        virtual ~IStringable() {}
        virtual std::string ToString() const = 0;
    };

    std::string to_string(IStringable const& v) { return v.ToString(); }

    void log(std::string_view const& sv)
    {
        std::cout << "debug: " << sv << '\n';
    }
    template<class T, std::enable_if_t<!std::is_convertible_v<T, std::string_view>, int> = 0>
    void log(T const& v)
    {
        using std::to_string;
        log(to_string(v));
    }
}

The idea is to use ADL and SFINAE to call either std::to_string or ISrtingable::ToString on the thing to log, and log the resultant string.

Usage:

class Person : public Logger::IStringable {
public:
    Person(const std::string name) : _name(name) { }
    virtual std::string ToString() const { return _name; }
private:
    std::string _name;
};

int main()
{
    Person p("Alice");
    double d = 0.0;
    const char* c = "Some words";

    Logger::log(p);
    Logger::log(d);
    Logger::log(c);
}

Demo: https://coliru.stacked-crooked.com/a/77e19e87c9d4780d

user_54705960
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