How to detect if a view is visible in a viewport or window in react native?

user_6477938 0
Viewed 20272

I want a similar feature just like react visibility sensor, but in react-native. I have a flat list with multiple items(each having different height). I want to detect whether a particular item(lets say 5th item) comes inside the view port and when it goes out

react-native
2 Answers

You can use onViewableItemsChanged to check which viewableItems are on the screen.

Here's a dummy class example:

class Demo extends Component {
  constructor() {
    super();
    this.viewabilityConfig = {
      viewAreaCoveragePercentThreshold: 95
    }
  }
  onViewableItemsChanged = ({ viewableItems }) => {
    // viewableItems will show you what items are in view
  }
  render() {
    <FlatList
      ...
      onViewableItemsChanged={this.onViewableItemsChanged}
      viewabilityConfig={this.viewabilityConfig}
    />
  }
}

You'll need to modify viewAreaCoveragePercentThreshold accordingly.

user_20267680

You can use Viewport from '@skele/components' like this:

0. Install Skele Components: yarn add @skele/components or npm install @skele/components

1. Wrap your scrollable view with Viewport.Tracker

    import { Viewport } from '@skele/components'
    ...
    render() {
        return (
            <Viewport.Tracker>
                <ScrollView scrollEventThrottle={16}>
                    { this.props.children }
                </ScrollView>
            </Viewport.Tracker>
        );
    }

2. Make its child components Viewport.Aware

import { Image } from 'react-native'
import { Viewport } from '@skele/components'
...
const ViewportAwareImage = Viewport.Aware(Image)
...
render() {
    return (
        <ViewportAwareImage
            source={{ uri: 'https://facebook.github.io/react-native/img/header_logo.png' }}
            onViewportEnter={() => console.log('Entered!')}
            onViewportLeave={() => console.log('Left!')} 
        />
    );
}

for more info visite this link

user_98895130
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