transport<- structure(list(date = structure(c(1L, 2L, 3L, 4L, 5L, 6L, 7L,
8L, 9L, 10L, 11L, 12L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L,
11L, 12L), .Label = c("01.01.2001", "01.02.2001", "01.03.2001",
"01.04.2001", "01.05.2001", "01.06.2001", "01.07.2001", "01.08.2001",
"01.09.2001", "01.10.2001", "01.11.2001", "01.12.2001"), class = "factor"),
Market_82 = c(7000L, 7272L, 7668L, 7869L, 8057L, 8428L, 8587L,
8823L, 8922L, 9178L, 9306L, 9439L, 3725L, 4883L, 8186L, 7525L,
6335L, 4252L, 5642L, 1326L, 8605L, 3501L, 1944L, 7332L),
transport = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L
), .Label = c("plane", "train"), class = "factor")), .Names = c("date",
"Market_82", "transport"), class = "data.frame", row.names = c(NA,
-24L))
let's create seasonalplot for each group(plane and train) separately
library(forecast)
par(mfrow = c(2, 1))
lapply(split(transport['Market_82'], transport$transport), seasonplot(ts(transport,frequency=12)))
then i get error
Error in match.fun(FUN) :
'seasonplot(ts(transport, frequency = 12))' is not a function, character or symbol
How to get seasonlap plot for two groups?
