Initialising Java String literal giving error

user_2512313 0
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This java string literal initializing giving error when the code to initialize is within checking if par1 has a value or not. I am not sure whether I am doing or its some other issue??

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public class optionalFields {

    public static void main(String args[])
    {
        optional_func(Optional.of(true));
    }

        public static void optional_func(Optional<Boolean> par1)
    {
        if(par1.isPresent())
            String s = "test";
        System.out.println(s);
    }
 }
optional-parameters java
1 Answers

It should be:

if (par1.isPresent()) {
    String s = "test";
    System.out.println(s);
}

You cannot declare a variable inside an if statement unless you put the declaration in a block. Besides, since you are printing s, the println statement should also be inside the block of the if statement.

If you want to print s even if the condition is false, it should be:

String s = null;
if (par1.isPresent())
    s = "test";
System.out.println(s);
user_12215710
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