Is There a Way to Just Evaluate the Argument to a Functor?

Question

Given foo which is a vector I want to evaluate it's contents with all_of. But all I'm really trying to check is that each element evaluates to true.

I can do this by using logical_not and none_of but I would rather not use double negatives, and it feels dumb to write a lambda: [](const auto param) -> bool { return param; }

Does the standard provide me a functor that does what I want?

user_4342498 · Answer

What you are looking for is std::identity which was added to C++20. It takes a parameter and returns it unchanged. It operator() looks like

template
constexpr T&& operator()( T&& t ) const noexcept;

and it returns

std::forward(t)

Is There a Way to Just Evaluate the Argument to a Functor?

1 Answers