How to use junction inside a perl6 regex interpolation?

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Sometimes I have a long list and I would like to check whether a string matches anything in the list. I am trying to interpolate a junction inside a regex. They are all errors.

say "12345" ~~ m/ <{ (2,3,4).any }> /
Cannot resolve caller MAKE_REGEX(Int, Bool, Bool, Int, PseudoStash); none of these signatures match:

say "12345" ~~ m/ $( (2,3,4).any ) /
This type cannot unbox to a native string: P6opaque, Junction

Does this error message mean that junctions cannot be used inside regex interpolation?

The work-around I have is

say "12345" ~~ m/ <{ (2,3,4).join("||") }> /
｢2｣

How can I use junctions inside regex interpolation?

junction raku interpolation regex
1 Answers

Sometimes I have a long list and I would like to check whether a string matches anything in the list.

Use a list, not a Junction:

my @list = <bar bartoo baragain>;
say 'bartoo' ~~ / @list /;                         # ｢bartoo｣
say 'bartoo' ~~ / <{<bar bartoo baragain>}> /;     # ｢bartoo｣

Note that by default you get the longest matching token.

I am trying to interpolate a junction inside a regex. They are all errors. ... Does this error message mean that junctions cannot be used inside regex interpolation?

I think so. (The error message is perhaps LTA.) Junctions are a feature of the main P6 language. It seems reasonable that the pattern matching DSL doesn't support them.

The work-around I have is

say "12345" ~~ m/ <{ (2,3,4).join("||") }> /
｢2｣

If you join with a doubled pipe (||) then you get the first token that matches rather than the longest:

say 'bartoo' ~~ / <{'bar || bartoo || baragain'}> /; # ｢bar｣
say 'bartoo' ~~ / ||@list /;                         # ｢bar｣
say 'bartoo' ~~ / ||<{<bar bartoo baragain>}> /;     # ｢bar｣

Not specifying the pipe symbol for these constructs is the same as specifying a single pipe symbol (|) and matches the longest matching token:

say 'bartoo' ~~ / <{'bar | bartoo | baragain'}> /; # ｢bartoo｣
say 'bartoo' ~~ / |@list /;                        # ｢bartoo｣
say 'bartoo' ~~ / |<{<bar bartoo baragain>}> /;    # ｢bartoo｣

You've asked related questions before. I'll add links to a couple of them here for convenience:

user_10776720
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