BeautifulSoup not finding xml tag, how do i fix this?

You can do:

import requests
from bs4 import BeautifulSoup as bs

url = 'https://launch.toytokyo.com/sitemap_pages_1.xml'

soup = bs(requests.get(url).content,'html.parser')


urls = [i.text for i in soup.find_all('loc')]

So basically I get the contents and locate loc tag that contains the urls, then I grab the content ;)

Updated: Required url tag and generate a dictionary

urls = [i for i in soup.find_all('url')]

s = [[{k.name:k.text} for k in urls[i] if not isinstance(k,str)] for i,_ in enumerate(urls)]

Use from pprint import pprint as print to get a beautiful print of s:

print(s)

Notes: you can use lxml parser as it is faster than html.parser

As an alternative to BeautifulSoup, you can always use xml.etree.ElementTree to parse your XML urls located at the loc tag:

from requests import get
from xml.etree.ElementTree import fromstring, ElementTree
from pprint import pprint

url = 'https://launch.toytokyo.com/sitemap_pages_1.xml'

req = get(url)
tree = ElementTree(fromstring(req.text))

urls = []
for outer in tree.getroot():
    for inner in outer:
        namespace, tag = inner.tag.split("}")
        if tag == 'loc':
            urls.append(inner.text)

pprint(urls)

Which will give the following URLs in a list:

['https://launch.toytokyo.com/pages/about',
 'https://launch.toytokyo.com/pages/help',
 'https://launch.toytokyo.com/pages/terms',
 'https://launch.toytokyo.com/pages/visit-us']

From this, you can group your info into a collections.defaultdict:

from requests import get
from xml.etree.ElementTree import fromstring, ElementTree
from collections import defaultdict
from pprint import pprint

url = 'https://launch.toytokyo.com/sitemap_pages_1.xml'

req = get(url)
tree = ElementTree(fromstring(req.text))

data = defaultdict(dict)
for i, outer in enumerate(tree.getroot()):
    for inner in outer:
        namespace, tag = inner.tag.split("}")
        data[i][tag] = inner.text

pprint(data)

Which gives the following defaultdict of dictionaries with indices as keys:

defaultdict(<class 'dict'>,
            {0: {'changefreq': 'weekly',
                 'lastmod': '2018-07-26T14:37:12-07:00',
                 'loc': 'https://launch.toytokyo.com/pages/about'},
             1: {'changefreq': 'weekly',
                 'lastmod': '2018-11-26T07:58:43-08:00',
                 'loc': 'https://launch.toytokyo.com/pages/help'},
             2: {'changefreq': 'weekly',
                 'lastmod': '2018-08-02T08:57:58-07:00',
                 'loc': 'https://launch.toytokyo.com/pages/terms'},
             3: {'changefreq': 'weekly',
                 'lastmod': '2018-05-21T15:02:36-07:00',
                 'loc': 'https://launch.toytokyo.com/pages/visit-us'}})

If you wish to instead group by categories, then you can use a defaultdict of lists instead:

data = defaultdict(list)
for outer in tree.getroot():
    for inner in outer:
        namespace, tag = inner.tag.split("}")
        data[tag].append(inner.text)

pprint(data)

Which gives this different structure:

defaultdict(<class 'list'>,
            {'changefreq': ['weekly', 'weekly', 'weekly', 'weekly'],
             'lastmod': ['2018-07-26T14:37:12-07:00',
                         '2018-11-26T07:58:43-08:00',
                         '2018-08-02T08:57:58-07:00',
                         '2018-05-21T15:02:36-07:00'],
             'loc': ['https://launch.toytokyo.com/pages/about',
                     'https://launch.toytokyo.com/pages/help',
                     'https://launch.toytokyo.com/pages/terms',
                     'https://launch.toytokyo.com/pages/visit-us']})

Another way using xpath

import requests
from lxml import html
url = 'https://launch.toytokyo.com/sitemap_pages_1.xml'
tree = html.fromstring( requests.get(url).content)
links = [link.text for link in tree.xpath('//url/loc')]
print(links)

I've tried to show exactly the way you have already tried. The only thing you need to rectify is webSite.text. You could get valid response if you used webSite.content instead.

This is the corrected version of your existing attempt:

import requests
from bs4 import BeautifulSoup

webSite = requests.get('https://launch.toytokyo.com/sitemap_pages_1.xml')
pageSource = BeautifulSoup(webSite.content, "xml")
for k in pageSource.find_all('url'):
    link = k.loc.text
    date = k.lastmod.text
    frequency = k.changefreq.text
    print(f'{link}\n{date}\n{frequency}\n')