Swift 4 Array Map nil to String

user_5834822 0
Viewed 185

so i have this simple code and have problem with swift data type, want to map this array from

 ["a", "b", nil, "c", "d", nil]

to

 ["a", "b", "z", "c", "d", "z"]

so, this is my current code

import Foundation

let array1 = ["a", "b", nil, "c", "d", nil]
let newArray = array1.map { (currentIndex: Any) -> String in
    if currentIndex == nil  {
        return "z"
    }
    return currentIndex as! String
}
print(newArray)

I am grateful if you try to solve the code. thank you.

swift arrays
2 Answers

If you declare currentIndex as Any then you cannot compare it against nil anymore. The correct type in your case would be String?: 

let newArray = array1.map { (currentIndex: String?) -> String in
    if currentIndex == nil  {
        return "z"
    }
    return currentIndex!
}

However, the compiler can infer that automatically from the context:

let newArray = array1.map { currentIndex -> String in
    if currentIndex == nil  {
        return "z"
    }
    return currentIndex!
}

Better use the nil-coalescing operator ??, and avoid force-unwrapping:

let newArray = array1.map { currentIndex in
    currentIndex ?? "z"
}

or shorter:

let newArray = array1.map { $0 ?? "z"  }
user_11874150

Your code is absolutely right but problem is that you need to pass optional argument in map statement like below and bingo your code completely work fine.

let array1 = ["a", "b", nil, "c", "d", nil]
let newArray = array1.map { (currentIndex: Any?) -> String in
    if currentIndex == nil  {
        return "z"
    }
    return (currentIndex as? String ?? "")
}
print(newArray)
user_31656360
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