How to create JWK from RSA Key pair?

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Suppose I have a python structure representing an RSA key pair as follows:

rsa_key_pair = {
    'private_key': '-----BEGIN PRIVATE KEY-----\nMIIEvAIBADAN__OBSCURED__qxu3sWAlY/bstTB5WfX8PA==\n-----END PRIVATE KEY-----\n',
    'public_key': 'ssh-rsa AAAAB3NzaC1yc2EAAAADAQABAAABAQDCDDqGTiBYyoB9T5Haow5gcPBIIiltLVyM4vo8Txia1czgrk2XGH5t4dsWrcXIXjQafNb7PKelXZdRU36vIIAaZCZ0As5LtkC5D93+KO9PFLGkHxWi2G43naR9hOnrKliMjOd+JRUdApdY8c/wYJbDxGGuw7W9e3MsLABFEK+TnPTVJtO8Ix78FiuHRooWfU5ph7clfTeyundN2BNv8mO6ZSBiBAk6tN8Fwpljs96Z/3HnMQutX1/AFkMn5h+E0EV4CgLPvtRazfzoWNlIiXGmiVUVHrM1wna9jT/jyb7aoxkthkAXb6NNyCW/Znxq45Ozy27kZcw/X4WQ0QMmpgfX'
}

How can I write python code that will produce the JWK that can be used to verify JWT signed with this RSA private key? The Algorithm used is RSA256.

This website mkjwk accomplishes what I'm trying to do. But I'm trying to do it in python code.

jwk jwt rsa python
1 Answers

Here is an example of how you can use Authlib to dumps a JWK:

from authlib.jose import jwk

jwk.dumps(rsa_key_pair['public_key'], kty='RSA')
jwk.dumps(rsa_key_pair['private_key'], kty='RSA')

Here is the result of your public key:

{
  "kty": "RSA",
  "n": "wgw6hk4gWMqAfU-R2qMOYHDwSCIpbS1cjOL6PE8YmtXM4K5Nlxh-beHbFq3FyF40GnzW-zynpV2XUVN-ryCAGmQmdALOS7ZAuQ_d_ijvTxSxpB8VothuN52kfYTp6ypYjIznfiUVHQKXWPHP8GCWw8RhrsO1vXtzLCwARRCvk5z01SbTvCMe_BYrh0aKFn1OaYe3JX03srp3TdgTb_JjumUgYgQJOrTfBcKZY7Pemf9x5zELrV9fwBZDJ-YfhNBFeAoCz77UWs386FjZSIlxpolVFR6zNcJ2vY0_48m-2qMZLYZAF2-jTcglv2Z8auOTs8tu5GXMP1-FkNEDJqYH1w",
  "e": "AQAB"
}

via http://docs.authlib.org/en/latest/jose/jwk.html

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