Spring Integration Java DSL: How to route with the channelMapping method to the channel which name is in the headers?

user_9601701 0
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How to route with the channelMapping method to the channel which name is in the headers? So if I try this

    @Bean
    private IntegrationFlow postDataToChannelX() {
            return f -> f
            ...
               .<String, Boolean> route(s -> s.equals("[]"), m -> m
                    .channelMapping(false, "headers['channelName']")
                    .channleMapping(true, ...);
    }

there comes

Caused by: org.springframework.messaging.core.DestinationResolutionException: failed to look up MessageChannel with name 'headers['channelName']' in the BeanFactory.; nested exception is org.springframework.beans.factory.NoSuchBeanDefinitionException: No bean named 'headers['channelName']' available

spring-integration-dsl spring-integration
1 Answers

You can just do like this:

.route(Message.class, (m) -> m.getHeaders().get("channelName"))

So, you don't need any mapping at all since you resolve to the target channel directly in the routing function.

user_27565470
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