How can I get an URL's host without schema and ending in php?

user_7425848 0
Viewed 582

I want to explode urls to get the host.

$link = str_replace("www.", "", $_POST['link']);
$part1 = explode("//", $link);
$part2 = explode(".", $part1[1]);
$host = $part2[0];

So if the $_POST['link'] is e.g.

https://www.youtube.com/watch?v=udm5jUA-2bs

I want to get just youtube. In this first way I get explode() expects parameter 2 to be string, array given" error message.

With this method:

$host = var_dump(parse_url($_POST['link'], PHP_URL_HOST));

I get www.youtube.com but I want only youtube.

explode url arrays php
3 Answers
  • Extract the url domain using parse_url() function with mode PHP_URL_HOST.
  • We will use explode() function to break it into parts using . as delimiter.
  • Now, the URL can be of two types, either youtube.com, or www.youtube.com, or %.youtube.com
  • We count the parts, and if they are two, we use the first value, else the second value.

DEMO: https://3v4l.org/KlErW

$url_host_parts = explode('.', parse_url($_POST['link'], PHP_URL_HOST));
$host = (count($url_host_parts) == 2) ? $url_host_parts[0] : $url_host_parts[1];
user_24693080

what about this without any regex? You can use parse_url() and explode() to get what you want i.e youtube

<?php
$url = 'https://www.youtube.com/watch?v=udm5jUA-2bs';
$parse = parse_url($url);
//print_r($parse);
echo explode('.',$parse['host'])[1];
?>

Output:

 youtube

DEMO: https://3v4l.org/kG1nD

user_11381920

You can use regex in preg_match() to do this work.

$url = "https://www.youtube.com/watch?v=udm5jUA-2bs";
preg_match("/(\w+)(?=\.\w{2,}(\/|\?|$))/", $url, $matches);
echo $matches[1]; // youtube

Check result in demo

user_51047480
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