Removing square brackets from hash array for value

user_5777540 0
Viewed 582

I am having a following hash array

A = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}

I tried following code to remove the square brackets

A.to_s.gsub("\\[|\\]", "")

also tried with code

p A.map { |hash| hash.each_with_object({}) { |(k, v), hash| hash[k] = v.first } }

but its not working.

How I remove the square brackets to get following output

A = [{"name" => "xx", "status" => "true"}, {"name" => "yy", "status" => "true"}

Kindly assist

hash ruby
1 Answers

Since they're strings inside arrays, the [] is the representation Ruby does of it. Try accessing the first element for each key's value in those hashes:

a = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}]
p a.map { |hash| hash.transform_values(&:first) }
# [{"name"=>"xx", "status"=>"true"}, {"name"=>"yy", "status"=>"true"}]

Depending on your Ruby version, you might not have transform_values available. A simple each_with_object would work similarly in that case:

p a.map { |hash| hash.each_with_object({}) { |(k, v), hash| hash[k] = v.first } }
# [{"name"=>"xx", "status"=>"true"}, {"name"=>"yy", "status"=>"true"}]
user_50251160
Related