I want to do exactly what has been in this post, except in Python. Consider two strings:
s1='AAA1
AAA2
AAA3'
s2='BBB1
BBB2
BBB3'
I want to have combine(s1,s2) to return:
s3='AAA1BBB1
AAA2BBB2
AAA3BBB3'
You may consider that these strings are actually very long and I want this processes to be performant. I would appreciate if you could help me know how to do this.
Multiline-strings are denoted with ''' in Python.
>>> s1 = '''AAA1
...:AAA2
...:AAA3'''
>>>
>>> s2 = '''BBB1
...:BBB2
...:BBB3'''
You can split them with str.splitlines and interleave them with zip.
>>> strings = [s1, s2]
>>> pairs = zip(*(s.splitlines() for s in strings))
>>> result = '\n'.join(''.join(pair) for pair in pairs)
>>>
>>> print(result)
AAA1BBB1
AAA2BBB2
AAA3BBB3
A generic function that accepts any number of multiline strings using the *args syntax can be written as follows.
>>> def combine(*strings):
...: lines = zip(*(s.splitlines() for s in strings))
...: return '\n'.join(''.join(line) for line in lines)
>>>
>>> str1 = '''A
...:D
...:H'''
>>> str2 = '''B
...:E
...:I'''
>>> str3 = '''C
...:F
...:J'''
>>>
>>> print(combine(str1, str2, str3))
ABC
DEF
HIJ
Note that zip truncates the iterable it produces to the length of its shortest argument, i.e. the result has as many lines as the shortest multiline string passed to combine.
If you expect strings with different numbers of lines and need fill-values, you can play around with zip_longest from the itertools module.
This may work for what you're looking to get if there's newlines involved:
s1="AAA1\nAAA2\nAAA3"
s2="BBB1\nBBB2\nBBB3"
ms1 = s1.splitlines()
ms2 = s2.splitlines()
new_list = []
i = 0
while i < 3:
new_list.append( ms1[i]+ms2[i] )
i = i + 1
print(new_list)
Use splitlines() and then zip two list together
s1="AAA1\nAAA2\nAAA3"
s2="BBB1\nBBB2\nBBB3"
l1 = s1.splitlines()
l2 = s2.splitlines()
print('\n'.join([i+j for i,j in zip(l1,l2)]))
Output
AAA1BBB1
AAA2BBB2
AAA3BBB3