How to use comprehension to find dict key when value is "None"?

user_6373357 0
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How to use comprehension to find dict key when value is None? Is there a one liner instead of the following code?

def Func():
    for k, v in some_dict.items()
        if not v:
            return k
dictionary python
2 Answers
result = next((k for k, v in some_dict.items() if not v), None)

This uses next to iterate over the generator and return the first k whose v is falsey, or None if no item matches that condition. If you prefer to raise an exception when no item matches, leave out the None default value.

user_4760

Try this (note empty lists will be None, and big lists default gets first element):

l=next((k for k, v in some_dict.items() if not v),None)
print(l)

Or:

l=next((k for k in some_dict.keys() if not some_dict[k]),None)
print(l)
user_87083640
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