For example 'a' has ASCII code 97 and we could use
char ch = 'a';
or
char ch = 97;
With auto we could write
auto ch = 'a';
for the first case, but how to get char variable by numerical ascii code during deduction?
This doesn't work for me:
auto ch = '\97';
You have to use octal or hex value for escape sequence
auto ch = '\141';
auto ch2 = '\x61';
For more info https://en.cppreference.com/w/cpp/language/escape
If you want to use decimal values, you have two options:
Cast to char
auto ch = static_cast<char>(97);
User-defined literals
char operator "" _ch(unsigned long num)
{
return static_cast<char>(num);
}
//...
auto ch = 97_ch;
There's no decimal escape, but you can use hexadecimal: '\x61', or octal, '\141'.
If you really need decimal, you need to cast; char{97}.
There is no integral literal that specifies a char. You have to explicitly name the type, e.g.
auto ch = char{97};