Turn a list of tuples into a list of its elements with list comprehension

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I'm currently studying for my exam in October and am confronting a problem I can't seem to figure out a good solution.

I want to read in a list of tuples of integers like this: [(1,2),(3,4),(5,6),..] and want the list comprehension to return [1,2,3,4,5,6,..]

The following works just fine but I want it to be in one list comprehension.

func :: [(Integer, Integer)] -> [Integer]
func xs = concat [ [x,y] | (x,y) <- xs ]

How can I make this work?

list-comprehension list haskell
1 Answers

You can use an extra iteration in the right part of the list comprehension, like:

func :: [(a, a)] -> [a]
func xs = [ xi | (x1, x2) <- xs, xi <- [x1, x2] ]

So we write list comprehension like people would write a nested loop in an imperative programming language.

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