I have a project with this structure:
--resources
--src
|
|-- mypackage.main
|
|-- MainClassOne.scala
|-- MainClassTwo.scala
|-- mypackage.utils
|
|-- SomeOne.scala
|-- SomeTwo.scala
I am trying to build two fat jars, with each one having its own Main class. Say jarOne.jar with MainClassOne and jarTwo.jar with MainClassTwo
Below are contents of my sbt file:
lazy val assemblySettings = Seq(
assemblyMergeStrategy in assembly := {
case "application.conf" => MergeStrategy.concat
case "defaults.conf" => MergeStrategy.concat
case PathList("UnusedStubClass.class") => MergeStrategy.discard
case x => val oldStrategy = (assemblyMergeStrategy in assembly).value
oldStrategy(x)
}
)
lazy val BuildOne = (project in file("."))
.settings(mainClass in Compile := Some("mypackage.main.MainClassOne"))
.settings(mainClass in assembly := Some("mypackage.main.MainClassOne"))
.settings(assemblyJarName in assembly := "jarOne.jar")
.settings(myMetaSettings: _*)
.settings(myScalaSettings: _*)
.settings(resolvers ++= myRepositories)
.settings(libraryDependencies ++= myDependencies)
.enablePlugins(AssemblyPlugin)
.settings(assemblySettings: _*)
lazy val BuildTwo = (project in file("."))
.settings(mainClass in Compile := Some("mypackage.main.MainClassTwo"))
.settings(mainClass in assembly := Some("mypackage.main.MainClassTwo"))
.settings(assemblyJarName in assembly := "jarTwo.jar")
.settings(myMetaSettings: _*)
.settings(myScalaSettings: _*)
.settings(resolvers ++= myRepositories)
.settings(libraryDependencies ++= myDependencies)
.enablePlugins(AssemblyPlugin)
.settings(assemblySettings: _*)
However, I note that this results in only one jar - jarTwo.jar - and not the two like I'd originally hoped.
The idea is to be able to build jars(with different names and main classes) from the same project. Appreciate inputs on how one could achieve this using sbt.