How do I delete a 2D or 3D pointer created with new? I know a 1D pointer can be deleted by delete [] name_of_pointer.
// 1D pointer:
int *pt1 = new int[size]; // Creating 1D pointer
delete [] pt1; // Deleting 1D pointer
// 3D pointer L: # of layers, R: # of rows, C: # of columns
int (*pt2)[L][R][C] = new int[1][L][R][C]; // L:2, R:2, C:3 (ex. below)
delete [] pt2;
I used this to create and delete a 3D pointer but it only removed the first two entries of pointer pt2, remaining 10 entries remained intact no matter how many times I ran the code.
Eg:
int B[2][2][3] = {{{0,1,2},{3,4,5}},{{6,7,8},{9,10,11}}};
int (*pb)[2][2][3] = new int[1][2][2][3];
for(int k=0; k<2; k++){
for(int j=0; j<2; j++){
for(int i=0; i<3; i++){
*(*(*(*(pb)+k)+j)+i) = B[k][j][i];
cout << "k,j,i: " << k << "," << j << "," << i;
cout << " " << B[k][j][i] << " " << *(*(*(*(pb)+k)+j)+i) << endl;
};
cout << endl;
};
cout << endl;
};
delete [] pb;
for(int k=0; k<2; k++){
for(int j=0; j<2; j++){
for(int i=0; i<3; i++){
cout << "k,j,i: " << k << "," << j << "," << i;
cout << " " << B[k][j][i] << " " << *(*(*(*(pb)+k)+j)+i) << endl;
};
cout << endl;
};
cout << endl;
};
I got garbage values for (k,j,i) = (0,0,0) & (0,0,1) after performing delete operation on pb, rest all 10 values remain unchanged.