Create new folder with pathlib and write files into it

user_8138305 0
Viewed 117514

I'm doing something like this:

import pathlib

p = pathlib.Path("temp/").mkdir(parents=True, exist_ok=True)

with p.open("temp."+fn, "w", encoding ="utf-8") as f:
    f.write(result)

Error message: AttributeError: 'NoneType' object has no attribute 'open'

Obviously, based on the error message, mkdir returns None.

Jean-Francois Fabre suggested this correction: 

p = pathlib.Path("temp/")
p.mkdir(parents=True, exist_ok=True)

with p.open("temp."+fn, "w", encoding ="utf-8") as f:
    ...

This triggered a new error message:

File "/Users/user/anaconda/lib/python3.6/pathlib.py", line 1164, in open opener=self._opener)
TypeError: an integer is required (got type str)

pathlib python-3.x
5 Answers

You can directly initialize filepath and create parent directories for parent attribute:

from pathlib import Path

filepath = Path("temp/test.txt")
filepath.parent.mkdir(parents=True, exist_ok=True)

with filepath.open("w", encoding ="utf-8") as f:
    f.write(result)
user_45423590

Maybe, this is the shortest code you want to do.

import pathlib

p = pathlib.Path("temp/")
p.mkdir(parents=True, exist_ok=True)
(p / ("temp." + fn)).write_text(result, encoding="utf-8")

In most cases, it doesn't need even open() context by using write_text() instead.

user_127218730

You can also do something like:

text_path = Path("random/results").resolve()
text_path.mkdir(parents=True, exist_ok=True)
(text_path / f"{title}.txt").write_text(raw_text)
user_13442950
Related