How can i extract values except double quotes in lua

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this is a string 

"'"id"':001 (it is visualized "id":001)

I want to capture only the values in lua. if there is not double quotes, i can extract values only. (use something:gmatch((%a+)%sd:%s(%d+)))

Is there anyone who solve this problem?

luci openwrt lua regex string
1 Answers

You may use a "(%w+)"%s*:%s*(%d+) pattern:

local example = [[ "id":001 "id2":002 ]]
for i,y in example:gmatch([["(%w+)"%s*:%s*(%d+)]]) do
  print(i, y)
end

See the Lua demo, output:

id  001
id2 002

The "(%w+)"%s*:%s*(%d+) pattern matches

  • " - a double quote
  • (%w+) - Group 1: one or more alphanumeric chars (use [%w_]+ to also match _)
  • " - a "
  • %s*:%s* - a colon enclosed with 0+ whitespaces
  • (%d+) - Group 2: one or more digits
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