Can you explain why the plot is stopping at J (at index 10)

user_1955372 0
Viewed 88

I am running this program to find the distribution of characters in a specific text.

# this is a paragraph from python documentation :)
mytext = 'When a letter is first k encountered, it is missing from the mapping, so the default_factory function calls int() to supply a default count of zero. The increment operation then builds up the count for each letter.The function int() which always returns zero is just a special case of constant functions. A faster and more flexible way to create constant functions is to use a lambda function which can supply any constant value (not just zero):'

d = dict()
ignorelist = ('(',')',' ', ',', '.', ':', '_')

for n in mytext:
    if(n not in ignorelist):
        n = n.lower()
        if n in d.keys():
            d[n] = d[n] + 1
        else:
            d[n] = 1
xx = list(d.keys())
yy = list(d.values())

import matplotlib.pyplot as plt
plt.scatter(xx,yy, marker = '*')
plt.show()

Both the list has 25 elements. For some strange reason the plot is coming like this. It ends in 'J' in x axis. enter image description here

If I zoom it the right side gets visible but there is no points plotted. enter image description here

scatter-plot matplotlib python-3.x
1 Answers

Note that this will be fixed as of matplotlib version 2.2

It seems you have found a bug in the new categorical feature of matplotlib 2.1. For single letter categories it will apparently limit its functionality to 10 items. If categories consist of more letters, this does not happen.

In any case, a solution is to plot numerical values (just as one would have needed to do prior to matplotlib 2.1 anyways). Then set the ticklabels to the categories.

# this is a paragraph from python documentation :)
mytext = 'When a letter is first k encountered, it is missing from the mapping, so the default_factory function calls int() to supply a default count of zero. The increment operation then builds up the count for each letter.The function int() which always returns zero is just a special case of constant functions. A faster and more flexible way to create constant functions is to use a lambda function which can supply any constant value (not just zero):'

d = dict()
ignorelist = ('(',')',' ', ',', '.', ':', '_')

for n in mytext:
    if(n not in ignorelist):
        n = n.lower()
        if n in d.keys():
            d[n] = d[n] + 1
        else:
            d[n] = 1

xx,yy = zip(*d.items())

import numpy as np
import matplotlib.pyplot as plt

xx_sorted, order = np.unique(xx, return_inverse=True)

plt.scatter(order,yy, marker="o")
plt.xticks(range(len(xx)), xx_sorted)
plt.show()

enter image description here

user_41243170
Related