RestTemplate response.getBody throws exception on 4** and 5** errors for put and post request but works fine for get requests

user_1002790 0
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I am trying to intercept and log all the request-responses. To make requests i am using RestTemplate.exchange().

When i make a GET request and get an 4** error i can call the ClientHttpResponse.getBody() and can access the response body but for PUT and POST requests ClientHttpResponse.getBody() method throws an exception.

What might be causing this and how can i get the response body for POST and PUT requests as well?

This is where i make the request:

apiResponse = restTemplate.exchange(url, vCloudRequest.getHttpMethod(), entity, responseType);

This is the part of the interceptor that gets the exception:

@Override
    public ClientHttpResponse intercept(HttpRequest request, byte[] body, ClientHttpRequestExecution execution) throws IOException {
        ClientHttpResponse response = execution.execute(request, body);

        String requestString = new String(body);

        String responseString = new 
// Below line throws exception
String(ByteStreams.toByteArray(response.getBody()), Charset.forName("UTF-8"));

This is the stack. 

Caused by: java.io.IOException: Server returned HTTP response code: 403 for URL: https://176.235.57.11/api/admin/org/bd154aaf-2e7c-446d-91be-f0a45138476b/users
    at sun.net.www.protocol.http.HttpURLConnection.getInputStream0(HttpURLConnection.java:1876)
    at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1474)
    at sun.net.www.protocol.https.HttpsURLConnectionImpl.getInputStream(HttpsURLConnectionImpl.java:254)
    at org.springframework.http.client.SimpleClientHttpResponse.getBody(SimpleClientHttpResponse.java:85)
    at org.springframework.http.client.BufferingClientHttpResponseWrapper.getBody(BufferingClientHttpResponseWrapper.java:69)
    at roma.api_utils.model.Interceptors.RequestLoggingInterceptor.intercept(RequestLoggingInterceptor.java:39)
    at org.springframework.http.client.InterceptingClientHttpRequest$InterceptingRequestExecution.execute(InterceptingClientHttpRequest.java:86)
    at org.springframework.http.client.InterceptingClientHttpRequest.executeInternal(InterceptingClientHttpRequest.java:70)
    at org.springframework.http.client.AbstractBufferingClientHttpRequest.executeInternal(AbstractBufferingClientHttpRequest.java:48)
    at org.springframework.http.client.AbstractClientHttpRequest.execute(AbstractClientHttpRequest.java:53)
    at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:652)

Update :

When i call response.getStatusCode() before calling response.getBody() it doesn't throw IOException.

resttemplate spring http java
4 Answers

For PUT and POST, it depends on your target resource. If your target resource do not add anything in the response's body after a PUT or POST request, it's normal to get an exception. In general, you know the resource that you send with PUT or POST so you can just check the response's status to know if your resource had been created or modified. You do not need to check the response body again.

user_66438030

You can use the following to accesss the response body in the interceptor. I did a quick unit test to confirm it works even on a POST with a 403 response.

However be careful, getBody returns an InputStream. Which means you can only read it once. You won't be able to read the same stream again outside the interceptor unless you provide a new response with a new body.

...
@Override
public ClientHttpResponse intercept(HttpRequest request, byte[] body, ClientHttpRequestExecution execution) throws IOException {
    final ClientHttpResponse response = execution.execute(request, body);
    final InputStream body = response.getBody();
    return response;
}
...
user_37654280
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