flask render_template with url parameter

user_2178552 0
Viewed 12464

I use pdf.js to render pdf in web. The format of the target url like this:

http://www.example.com/book?file=abc.pdf

My problem is: I use flask template to generate page using:

return render_template('book.html', paraKey=paraValue)

But how to attach url parameter "file=abc.pdf" to url? The parameter will be read by viewer.js(included in book.html) that uses it to read file for rendering pdf.

I'm new to flask, hoping guys giving me some help!

pdf.js flask templates
3 Answers

You could use redirect function, which can redirect you whatever you want:

@app.route('/book')
def hello():
    file = request.args.get('file')
    if not file:
        return redirect("/?file=abc.pdf")
    return render_template('book.html', paraKey=paraValue)
user_2729330

You can get the parameter that have been passed in the request url by using the request object. 

    @app.route("/book", methods=["GET"])
    def get_book():
        file = request.args.get("file")
        if file:
            return render_template('book.html', file=file)
        abort(401, description="Missing file parameter in request url")
user_85010560

This topic helped me reslove my question, but it seems not the perfect answer. code viewer.py not changed.Solution is:

step1)I embed the code

<script>var FILE_PATH = {{ file }}</script>

in template.

step2)the script that will use the variable need to modify the code(viewer.js),from:

var file = 'file' in params ? params.file : DEFAULT_URL

to

var file = FILE_PATH ? FILE_PATH: DEFAULT_URL

It let viewer.js not independent anymore.

I hope someone provide a better solution.

user_21785520
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