Mapping Spark DataSet row values into new hash column

user_491160 0
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Given the following DataSet values as inputData:

column0 column1 column2 column3
A       88      text    99
Z       12      test    200
T       120     foo     12

In Spark, what is an efficient way to compute a new hash column, and append it to a new DataSet, hashedData, where hash is defined as the application of MurmurHash3 over each row value of inputData.

Specifically, hashedData as:

column0 column1 column2 column3 hash
A       88      text    99      MurmurHash3.arrayHash(Array("A", 88, "text", 99))
Z       12      test    200     MurmurHash3.arrayHash(Array("Z", 12, "test", 200))
T       120     foo     12      MurmurHash3.arrayHash(Array("T", 120, "foo", 12))

Please let me know if any more specifics are necessary.

Any help is appreciated. Thanks!

spark-dataframe apache-spark-dataset apache-spark scala
2 Answers

One way is to use the withColumn function:

import org.apache.spark.sql.functions.{col, hash}
dataset.withColumn("hash", hash(dataset.columns.map(col):_*))
user_34439980

Turns out that Spark already has this implemented as the hash function inside package org.apache.spark.sql.functions

/**
 * Calculates the hash code of given columns, and returns the result as an int column.
 *
 * @group misc_funcs
 * @since 2.0
 */
@scala.annotation.varargs
def hash(cols: Column*): Column = withExpr {
  new Murmur3Hash(cols.map(_.expr))
}

And in my case, applied as:

import org.apache.spark.sql.functions.{col, hash}

val newDs = typedRows.withColumn("hash", hash(typedRows.columns.map(col): _*))

I truly have a lot to learn about Spark sql :(.

Leaving this here in case someone else needs it. Thanks!

user_4911600
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