Laravel collection filter by condition and split

user_3549177 0
Viewed 11897

I have a collection and each item has a featured attribute which is either true or false, so I want to get two variables $featured and $unfeatured.

I can do this:

$featured = $collection.filter(function($item){
   return $item->featured;
});

$unfeatured = $collection.filter(function($item){
   return !$item->featured;
});

But maybe there's a shorter way?

laravel php
2 Answers

I know this is quite an old post. Thought I would add this for folks coming to this from search.

Since 5.3 you can use the partition method like so:

list($featured, $unfeatured) = $collection->partition(function($item) {
    return $item->featured;
});

https://laravel.com/docs/5.3/collections#method-partition

user_103334170

You could use the each() method

$featured = [];
$unfeatured = [];

$collection->each(function ($item) use (&$featured, &$unfeatured) {
    if ($item->featured) {
        $featured[] = $item;
    } else {
        $unfeatured[] = $item;
    }
}
user_58088940
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