xoring a slice in Go

user_2744994 0
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So I'm trying to xor random, which is 4 bytes, with every four bytes of something. The thing is, I want to change random to ans (which is the result of the xor) and then keep going. So basically the random variable will be a fixed number the first time but will change afterwards until the loop ends. My code seems to have the correct logic, however, I keep getting (operator ^ not defined on slice)

random := 4 bytes
for j:=0;j<len(something);j+=4{
ans:=something[j:j+4] ^ random
random=ans
}

My guess is, slice doesn't allow xor, and something will have to be slice since I'm kind of slicing the array into multiple bytes. Any idea how to solve this problem?

go algorithm
1 Answers

The application should xor the individual bytes. Something like this:

var random [4]byte
for i, b := range something {
    random[i&3] ^= b  // xor b on element of random
}

This sets 

random[0] = random[0] ^ something[0] ^ something[4] ....
random[1] = random[1] ^ something[1] ^ something[5] ...
... and so on
user_57289910
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