How to "bin" the bellow array in numpy so that:
import numpy as np
bins = np.array([-0.1 , -0.07, -0.02, 0. , 0.02, 0.07, 0.1 ])
array = np.array([-0.21950869, -0.02854823, 0.22329239, -0.28073936, -0.15926265,
-0.43688216, 0.03600587, -0.05101109, -0.24318651, -0.06727875])
That is replace each of the values in array with the following:
-0.1 where `value` < -0.085
-0.07 where -0.085 <= `value` < -0.045
-0.02 where -0.045 <= `value` < -0.01
0.0 where -0.01 <= `value` < 0.01
0.02 where 0.01 <= `value` < 0.045
0.07 where 0.045 <= `value` < 0.085
0.1 where `value` >= 0.085
The expected output would be:
array = np.array([-0.1, -0.02, 0.1, -0.1, -0.1, -0.1, 0.02, -0.07, -0.1, -0.07])
I recognise that numpy has a digitize function however it returns the index of the bin not the bin itself. That is:
np.digitize(array, bins)
np.array([0, 2, 7, 0, 0, 0, 5, 2, 0, 2])