equivalent of getbuffer for BytesIO in Python 2

see critical update below

After digging in python 2.7 source code I found a simple solution: because io.BytesIO() returns a file descriptor, it has a standard set of functions including tell().

Note that indirect methods such as len(fd.getvalue()) or fd.getbuffer().nbytes copy buffer out and then compute buffer size. In my case, when the buffer holds 1/2 of the memory, this ends up as an application crash :/

Contrary fd.tell() just reports a current position of the descriptor and do not need any memory allocation!

Note that both sys.getsizeof(fd), fd.__sizeof__() do not return correct bufer size.

>>> from io  import BytesIO
>>> from sys import getsizeof
>>> with BytesIO() as fd:              
...  for x in xrange(200):
...   fd.write(" ")
...   print fd.tell(), fd.__sizeof__(), getsizeof(fd)
1 66 98
2 66 98
3 68 100
4 68 100
5 70 102
6 70 102
.....
194 265 297
195 265 297
196 265 297
197 265 297
198 265 297
199 265 297
200 265 297

UPDATE

After @admaster and @Artemis comments I realized that the correct method, in case of preset buffer, is to move the pointer to the end of the buffer. Standard seek function can do that, ant it will report the current buffer size

buffsize = fd.seek(0,2)

So here how it should be done without unnecessary coping memory

from io import BytesIO
x = BytesIO(b'AAAAAA')
x.seek(0,2) # returns 6
x.tell()    # returns 6

# However
x = BytesIO()
x.write(b'AAAAAA')
x.seek(0,2) # returns 6
x.tell()    # returns 6

You can use getvalue()

Example:

from io import BytesIO
if __name__ == "__main__":
    out = BytesIO()
    out.write(b"test\0")
    print len(out.getvalue())

See: https://docs.python.org/2/library/io.html#io.BytesIO.getvalue

Its worth noting that tell() will only return you the current position of the file descriptor and not necessarily the size of the buffer.

This can be seen in the following example:

from io import BytesIO
x = BytesIO(b'AAAAAA')
x.tell() # returns 0
x.read()
x.tell() # Now it returns 6

# However
x = BytesIO()
x.write(b'AAAAAA')
x.tell() # returns 6

In the first example we have initialised the object with our byte string but the file descriptor is still at the beginning hence returning 0, we then read the stream which means our file descriptor will have moved to the end, as a result it returns 6.

In the second example we initialise an empty BytesIO object and write our bytes string to it, as a result the file descriptor is now at the end of the stream and so we don't need to read it to update the descriptor.