Combine model's condition with its association's condition in Sequelize

Is there a way to find models by a condition that applies to its own field or to its association's field?

Given models Model and Association, where each Model has one Association.

const Model = sequelize.define('model', {
    name: sequelize.STRING,
});

const Association = sequelize.define('association', {
    name: sequelize.STRING,
});

Association.belongsTo(Model);
Model.hasOne(Association);

I want to find all Models, that either has a name equal to "text", or has an Association with a name equal to "text".

So far I come up with the solution with Sequelize.literal, that doesn't look robust enough.

Model.findAll({
    attributes: ['id', 'name'],
    include: [{
        model: Association,
        attributes: [],
    }],
    where: {
        $or: [
            { name: 'test' },
            Sequelize.literal('association.name = \'test\''),
        ],
    },
});

Is there a better way?