How to replace URL parameters in a thymeleaf link?

user_1194415 0
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I have an existing URL with get parameters. On a button click, I want to change one specific URL parameter, but retain the others. Is that possible?

Thymeleaf template:

<a th:href="@{/order/details(id=3)}">

Results in:

<a href="/order/details?id=3">

What if I want to

  • preserve other parameters in the URL
  • override the id parameter?

Desired result of the thymeleaf template above:

localhost:8080/order/details?name=test&id=3

Preferably without javascript.

thymeleaf spring java
2 Answers

Even though it's an older question, I hope this could still help:

<a th:href="@{${urlBuilder.replaceQueryParam('id', 3).build().toUriString()}}" th:with="urlBuilder=${T(org.springframework.web.servlet.support.ServletUriComponentsBuilder).fromCurrentRequest()}">

This builds a complete URI string, including the HTTP(S) part. So if you use (for example) a load balancer for your web applications and it doesn't forward https requests directly, you will get a wrong URI string. In this case, you have to do it like Zico wrote: Set the baseUrl in the controller and bind it to the template. You could also get the query string from the current request: request.getQueryString() or use the ServletUriComponentsBuilder class in your controller.

Edit

You can apply .scheme('https') to urlBuilder (@{${urlBuilder.replaceQueryParam('id', 3).scheme('https').build().toUriString()}}). E.g. you can create a method in your controller which gets the X-Forwarded-Proto from your load balancer.

Check example #27 from here: https://www.programcreek.com/java-api-examples/?api=org.springframework.web.servlet.support.ServletUriComponentsBuilder

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