Consequences of uninitialised variables: int vs unsigned char

I saw the following example on cppreference.com

int x;     // OK: the value of x is indeterminate
int y = x; // undefined behavior

Here, int y = x; is undefined behavior because x is uninitialized.

But,

unsigned char c;     // OK: the value of c is indeterminate
unsigned char d = c; // OK: the value of d is indeterminate

Here, unsigned char d = c; is indeterminate behavior, but unsigned char c; is also an uninitialized variable.

So, Why is the value of unsigned char d indeterminate?