What's going on here? Why isn't $c == 1 ?
$ cat y.pl
#!/usr/bin/perl
$a = 0;
$b = 1;
$c = $a xor $b;
print "$a ^ $b = $c\n";
$ ./y.pl
0 ^ 1 = 0
Perl xor returns unexpected result
Viewed 386
2 Answers
Related
What's going on here? Why isn't $c == 1 ?
$ cat y.pl
#!/usr/bin/perl
$a = 0;
$b = 1;
$c = $a xor $b;
print "$a ^ $b = $c\n";
$ ./y.pl
0 ^ 1 = 0