Get POSIX path of active Finder window with JXA AppleScript

Question

I would like the JXA equivalent of this AppleScript snippet:

tell application "Finder"

    # Get path
    set currentTarget to target of window 1
    set posixPath to (POSIX path of (currentTarget as alias))

    # Show dialog
    display dialog posixPath buttons {"OK"}

end tell

The closest I got was using the url property to initialize a Foundation NSURL object and access its fileSystemRepresentation property like so:

// Get path
var finder = Application('Finder')
var currentTarget = finder.finderWindows[0].target()
var fileURLString = currentTarget.url()

// I'd like to get rid of this step
var fileURL = $.NSURL.alloc.initWithString(fileURLString)
var posixPath = fileURL.fileSystemRepresentation

// Show dialog
finder.includeStandardAdditions = true
finder.displayAlert('', {buttons: ['Ok'], message: posixPath})

But this seems unnecessarily complex. Is there a nicer way to get to the POSIX path without using Foundation API or manual string wrangling?

If I naively try this:

finder.finderWindows[0].target().posixPath()

I get this error:

app.startupDisk.folders.byName("Users").folders.byName("kymer").folders.byName("Desktop").posixPath()
        --> Error -1728: Can't get object.

This SO answer seems relevant, but I can't seem to adapt it to fit my needs:

App = Application.currentApplication()
App.includeStandardAdditions = true
SystemEvents = Application('System Events')

var pathToMe = App.pathTo(this)
var containerPOSIXPath = SystemEvents.files[pathToMe.toString()].container().posixPath()

Any help would be greatly appreciated!

user_1800086 · Answer

(() => {

    // getFinderDirectory :: () -> String
    const getFinderDirectory = () =>
        Application('Finder')
        .insertionLocation()
        .url()
        .slice(7);

    return getFinderDirectory();
})();

Get POSIX path of active Finder window with JXA AppleScript

5 Answers