Kotlin || How to distinguish the view id from onClick() like switch statement in Android?

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As we know in Android we are using the switch statement to distinct the view like below, We used to implement View.OnClickListener to get onClick interface method to perform any task

 @Override
    public void onClick(View view) {

        switch (view.getId()) {
            case R.id.imgBack:

              ///DO SOME THING HERE

                break;

            case R.id.btnSubmit:

                ///DO SOME THING HERE

                break;
        }
    }

Same thing i am using in Kotlin , by implement the View.OnClickListener and getting its overrided method like below

class FeedBackActivity : AppCompatActivity(), View.OnClickListener {
    override fun onClick(p0: View?) {

 /// HOW CAN I USE THE SWITCH STATEMENT TO DISTINGUISH THE VIEW CLICK 

    }

    override fun onCreate(savedInstanceState: Bundle?) {
        super.onCreate(savedInstanceState)
        setContentView(R.layout.feed_back_screen)

        imgBack.setOnClickListener(this)


    }

}

In above code i want to use the same switch to distinguish the different view click. How can i archive this in Kotlin

I know there is another way to perform the click listener in Kotlin like below

MY_VIEW.setOnClickListener {
                Toast.makeText(this,"I have clicked",Toast.LENGTH_LONG).show()
            }

But i want to use the same interface in Kotin which we are using the Android.Please help me to short out from this problem

2 Answers
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