Assume std::vector didnt have a value_type. Is is possible to write a template to deduce the value_type? Or more general, given a T<X>, how can I deduce X?
A very naive..
template <template <typename X> T>
void test(T<X> t) {
X x;
}
will probably make anybody who knows a bit about templates laugh at my foolish attempt and when instantiated like this:
int main() {
std::vector<int> x;
test(x);
}
create the following errors:
error: expected ‘class’ before ‘T’
template < template<typename X> T>
^
error: ‘X’ was not declared in this scope
void test(T<X> u) {
^
error: template argument 1 is invalid
void test(T<X> u) {
^
In function ‘void test(int)’:
error: ‘X’ was not declared in this scope
X x;
^
error: expected ‘;’ before ‘x’
X x;
^
In function ‘int main()’:
error: no matching function for call to ‘test(std::vector<int>&)’
test(x);
^
note: candidate is:
note: template<template<class X> class T> void test(int)
void test(T<X> u) {
^
note: template argument deduction/substitution failed:
note: cannot convert ‘x’ (type ‘std::vector<int>’) to type ‘int’
EDIT: the first one is easy to fix, but fixing it wont affect the others...
PS: I think I have a small misunderstanding, as std::vector<int> isnt a template, but a concrete type. However, still I would like to know if there is a way to get the int from a someTemplate<int> with some template magic.