How to get first match with sed?

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I am tired of this sed :D So I have a small file:

version = "1.1"
group= "com.centurion.eye"
archivesBaseName = "eye"

impmet {
    version = "4.1614"
    runDir = "eclipse"
}

And here is my sed command:

sed -n -e '/version/ s/.* = *//p' "build.gradle"

And I need to get ONLY version 1.1. So when I execute this command, the output is:

"1.3"
"4.1614"

But desired one is:

"1.3"

How can I achieve that? Thanks!

3 Answers
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