Flatten pandas DataFrame without pivot table

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I have a MultiIndex pandas DataFrame after calling groupby, and need to flatten it in a fashion similar to flattening a pivot table. Most of the analysis is already built around the grouped object, so would prefer to not have to refactor into a pivot table.

Consider some dummy data,

dummy_data = pd.DataFrame({'Ccy' : ['EUR', 'EUR', 'CAD', 'CAD', 'EUR', 'EUR', 'CAD', 'EUR'],
                  'Venue' : ['BAML']*5 + ['BARX']*3,
                  'Price': np.abs(np.random.randn(8)),
                  'volume': np.abs(10*np.random.randn(8))
                   }, 
                  index = pd.date_range('7/19/2017', periods=8))

dummy_data.index.name = "datetime"
print dummy_data


>>>            Ccy     Price Venue     volume
datetime                                  
2017-07-19  EUR  1.338521  BAML  11.227553
2017-07-20  EUR  0.882715  BAML   0.307711
2017-07-21  CAD  0.977815  BAML  14.196170
2017-07-22  CAD  1.262272  BAML   0.055213
2017-07-23  EUR  0.752433  BAML   5.315777
2017-07-24  EUR  0.699008  BARX   2.299045
2017-07-25  CAD  1.625567  BARX   6.474822
2017-07-26  EUR  2.122562  BARX   5.026135

The goal is to group data by Ccy and Venue, apply a filter operation to each subgroup, and then flatten the groups back into the format of this original frame. Consider a simple filter that retains rows where price > 0.8

dummy_data.groupby(['Ccy', 'Venue']).apply(lambda x: x[x['Price'] > 0.8])

>>>                      Ccy     Price Venue     volume
Ccy Venue datetime                                  
CAD BAML  2017-07-21  CAD  0.977815  BAML  14.196170
          2017-07-22  CAD  1.262272  BAML   0.055213
    BARX  2017-07-25  CAD  1.625567  BARX   6.474822
EUR BAML  2017-07-19  EUR  1.338521  BAML  11.227553
          2017-07-20  EUR  0.882715  BAML   0.307711
    BARX  2017-07-26  EUR  2.122562  BARX   5.026135

All I need now is to fill-in/flatten the Ccy and Venue columns such that

Ccy Venue datetime                                  
CAD BAML  2017-07-21  ...                       CAD BAML 2017-07-21  ...
          2017-07-22  ...                       CAD BAML 2017-07-22  ... 
    BARX  2017-07-25  ...    ---> BECOMES --->  CAD BARX 2017-07-25 ...
EUR BAML  2017-07-19  ...                       EUR BAML 2017-07-19 ... 
          2017-07-20  ...                       EUR BAML 2017-07-20  ...

I need to do this because we have a range of plotting utilities that aren't flexible enough to handle grouped data. Shouldn't there be an ungroup() or flatten() method that is reciprocal to the groupby() operation?

Note: the trivial filter in this example could have been applied to the ungrouped data. In reality, my filter is more complex and only makes sense on subgroups.


Solution Attempts (Attempts 1 and 2 from pivot table solution)

Attempt 1: melt method loses the datetime index.

    print dummy_data.groupby(['Ccy', 'Venue']).apply(lambda x: x[x['Price'] > 0.8]).melt()

>>>   variable      value
0       Ccy        CAD
1       Ccy        CAD
2       Ccy        CAD
3       Ccy        EUR
4       Ccy        EUR
5       Ccy        EUR
6     Price   0.977815
7     Price    1.26227
8     Price    1.62557
9     Price    1.33852

Attempt 2: the accepted answer leads to a KeyError

dummy_data.groupby(['Ccy', 'Venue']).apply(lambda x: x[x['Price'] > 0.8]).unstack().reset_index().drop('level_0', axis=1)

KeyError: 'level_0'

Attempt 3: reset_index() leads to ValueError

dummy_data.groupby(['Ccy', 'Venue']).apply(lambda x: x[x['Price'] > 0.8]).reset_index()

ValueError: cannot insert Venue, already exists

Attempt 4: as_index=False (without group_keys keyword)

out = dummy_data.groupby(['Ccy', 'Venue'], as_index=False).apply(lambda x: x[x['Price'] > 0.8])
print out
print out.index

              Ccy     Price Venue     volume
  datetime                                  
0 2017-07-21  CAD  0.977815  BAML  14.196170
  2017-07-22  CAD  1.262272  BAML   0.055213
1 2017-07-25  CAD  1.625567  BARX   6.474822
2 2017-07-19  EUR  1.338521  BAML  11.227553
  2017-07-20  EUR  0.882715  BAML   0.307711
3 2017-07-26  EUR  2.122562  BARX   5.026135
MultiIndex(levels=[[0, 1, 2, 3], [2017-07-19 00:00:00, 2017-07-20 00:00:00, 2017-07-21 00:00:00, 2017-07-22 00:00:00, 2017-07-25 00:00:00, 2017-07-26 00:00:00]],
           labels=[[0, 0, 1, 2, 2, 3], [2, 3, 4, 0, 1, 5]],
           names=[None, u'datetime'])

This gets me very close, but this object is still MultiIndexed. How can we just get the datetime index back?

1 Answers
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