How to transform a list of dicts into a list of tuples?

I have a list of dictionaries like this:

l = [{'pet': 'cat', 'price': '39.99', 'available': 'True'}, 
{'pet': 'cat', 'price': '67.99', 'available': 'True'}, 
{'pet': 'dog', 'price': '67.00', 'available': 'False'}
,....,
{'pet': 'fish', 'price': '11.28', 'available': 'True'}]

How can I transform the above list into? (*):

l_2 = [('cat','39.99','True'),('cat','67.99','True'),('dog','67.00','False'),....,('fish','11.28','True')]

I tried to use .items() and l[1]:

for l in new_list:
        new_lis.append(l.items())

However, I was not able to extract the second element position of the list of dictionaries into a list of tuples, as (*)