I have a dataframe that looks like this, but with 26 rows and 110 columns:
index/io 1 2 3 4
0 42 53 23 4
1 53 24 6 12
2 63 12 65 34
3 13 64 23 43
Desired output:
index io value
0 1 42
0 2 53
0 3 23
0 4 4
1 1 53
1 2 24
1 3 6
1 4 12
2 1 63
2 2 12
...
I have tried with dict and lists by transforming the dataframe to dict, and then create a new list with index values and update in new dict with io.
indx = []
for key, value in mydict.iteritems():
for k, v in value.iteritems():
indx.append(key)
indxio = {}
for element in indx:
for key, value in mydict.iteritems():
for k, v in value.iteritems():
indxio.update({element:k})
I know this is too far probably, but it's the only thing I could think of. The process was too long, so I stopped.