Item position in list

I have this dictionary:

db= {'www.baurom.ro':
                     {0: [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
                      1: [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
                     },
    'slbz2':
            {0: [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
             1: [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
    }

And a list:

lista=['www.baurom.ro', 'www.baurom.ro', 'www.baurom.ro', 'www.baurom.ro', 'www.baurom.ro', 'www.baurom.ro', 'www.baurom.ro', 'www.listafirme.ro', 'www.romanian-companies.eu', 'www.risco.ro']

What am i doing now is this:

for x in lista:
     if x in db:
        db[x][0][lista.index(x)]+=1

In other words i want to count how many times each site appears in the list and on which position. This works but in the given example it will return something like:

{0: [7, 0, 0, 0, 0, 0, 0, 0, 0, 0]

while i would want it to be:

{0: [1, 1, 1, 1, 1, 1, 1, 0, 0, 0]

How can i achieve this? I can use a variable, initiate it with var=0 and then +=1 and use it as an artificial index but is there a more "pythonic" way of doing it?