Can the compiler exploit empty base optimisation if the class contains a member of the base class?

Consider

struct base {};
struct child : base {};

It's well-known that sizeof(child) can be 1 by application of the empty base optimisation.

Now however, consider

struct base {};
struct child : base {base b;};

Can the compiler apply the empty base optimisation now, or must sizeof(child) be at least 2?

Reference: http://en.cppreference.com/w/cpp/language/ebo