Index out of range when using lambda

Viewed 4797

I'm a little confused about lambda operators in Python right now. The following (working) code sorts a list of tuples after the number of occurrences of a tuples first element over the first elements of all tuples:

tuples = [(2, 1, 8, 4), (3, 4, 8, 1), (3, 8, 1, 4), (4, 1, 8, 3),
              (4, 8, 1, 3), (8, 8, 3, 1), (8, 1, 3, 4), (8, 4, 1, 3),
              (8, 4, 3, 1)]

temp = list(zip(*tuples))    
tuples.sort(key=lambda x: temp[0].count(x[0])
                ,reverse=True)

print(tuples)

However, if I now try to skip the creating of "temp", i.e write this:

tuples = [(2, 1, 8, 4), (3, 4, 8, 1), (3, 8, 1, 4), (4, 1, 8, 3),
              (4, 8, 1, 3), (8, 8, 3, 1), (8, 1, 3, 4), (8, 4, 1, 3),
              (8, 4, 3, 1)]

tuples.sort(key=lambda x: list(zip(*tuples))[0].count(x[0])
                ,reverse=True)

print(tuples)

It throws an error:

Traceback (most recent call last):
  File "E:\Python-Programms\Sorting", line 6, in <module>
    ,reverse=True)
  File "E:\Python-Programms\Sorting", line 5, in <lambda>
    tuples.sort(key=lambda x: list(zip(*tuples)) [0].count(x[0])
IndexError: list index out of range

Why does this error occur?

2 Answers
Related