How to prevent the constructor from creating an object when an exception is thrown

When a constructor throws an exception, how can I prevent the object from being created?

In the example below, I create a Month() class, for which legal values of the int month_ property are in the range of 1 to 12. I instantiate December, or dec, with integer value 13. The exception is thrown, as it should be, but the object is still created. The destructor is then called.

How do I abort creation of a class instance upon a thrown exception?

OUTPUT

-- Month() constructor called for value: 2
-- Month() constructor called for value: 6
-- Month() constructor called for value: 13
EXCEPTION: Month out of range
2
6
13
-- ~Month() destructor called.
-- ~Month() destructor called.
-- ~Month() destructor called.
Press any key to exit

Minimal, complete, and verifiable example

#include <iostream>
#include <string>

class Month {

    public:
        Month(int month) {
            std::cout << "-- Month() constructor called for value: " << month << std::endl;
            try {
                // if ((month < 0) || month > 12) throw 100; Good eye, Nat!
                if ((month < 1) || month > 12) throw 100;
            } catch(int e) {
                if (e == 100) std::cout << "EXCEPTION: Month out of range" << std::endl;
            }
            month_ = month;
        }

        ~Month() {
            std::cout << "-- ~Month() destructor called." << std::endl;
        }

        int getMonth()const { return month_; }

    private:
        int month_;
};

int makeMonths() {
    Month feb(2), jun(6), dec(13);
    std::cout << feb.getMonth() << std::endl;
    std::cout << jun.getMonth() << std::endl;
    std::cout << dec.getMonth() << std::endl;
    return 0;
}

int main() {
    makeMonths();
    std::cout << "Press any key to exit"; std::cin.get();
    return 0;
}